Jackson：如何生成拒绝所有附加内容的 json 模式

Java
import com.fasterXML.jackson.databind.JSonNode;
import com.fasterXML.jackson.databind.ObjectMapper;
import com.fasterXML.jackson.databind.node.ObjectNode;
public class JSonSchemaGenerator {
    public static void mAIn(String[] args) throws Exception {
        ObjectMapper objectMapper = new ObjectMapper();
        JSonNode schema = generateJSonSchema(objectMapper.readTree("{\"name\":\"John\",\"age\":25,\"emAIl\":\"john@example.com\"}"));
        System.out.println(schema);
    }
    private static JSonNode generateJSonSchema(JSonNode JSonNode) {
        if (JSonNode.isObject()) {
            ObjectNode objectNode = (ObjectNode) JSonNode;
            ObjectNode schema = objectNode.objectNode();
            
            for (String fieldName : objectNode.fieldNames()) {
                JSonNode fieldValue = objectNode.get(fieldName);
                schema.set(fieldName, generateJSonSchema(fieldValue));
            }
            
            return schema;
        } else {
            return JSonNode;
        }
    }
}