Swift - 通过重复生成组合

Swift
func generateBinaryCombinations(_ n: Int) -> [[Int]] {
    var combinations: [[Int]] = []
    
    for i in 0..<Int(pow(2, Double(n))) {</p>        var binary: [Int] = []
        
        for j in 0..<n {</p>            let bit = (i >> j) & 1
            binary.append(bit)
        }
        
        combinations.append(binary)
    }
    
    return combinations
}
let n = 3
let binaryCombinations = generateBinaryCombinations(n)
print(binaryCombinations)